(x^3-3x)(2x+1)=0

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Solution for (x^3-3x)(2x+1)=0 equation: 


Simplifying
(x3 + -3x)(2x + 1) = 0

Reorder the terms:
(-3x + x3)(2x + 1) = 0

Reorder the terms:
(-3x + x3)(1 + 2x) = 0

Multiply (-3x + x3) * (1 + 2x)
(-3x * (1 + 2x) + x3(1 + 2x)) = 0
((1 * -3x + 2x * -3x) + x3(1 + 2x)) = 0
((-3x + -6x2) + x3(1 + 2x)) = 0
(-3x + -6x2 + (1 * x3 + 2x * x3)) = 0
(-3x + -6x2 + (1x3 + 2x4)) = 0
(-3x + -6x2 + 1x3 + 2x4) = 0

Solving
-3x + -6x2 + 1x3 + 2x4 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), 'x'.
x(-3 + -6x + x2 + 2x3) = 0


Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying
x = 0

Subproblem 2
Set the factor '(-3 + -6x + x2 + 2x3)' equal to zero and attempt to solve:

Simplifying
-3 + -6x + x2 + 2x3 = 0

Solving
-3 + -6x + x2 + 2x3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
x = {0}

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